Optimal. Leaf size=323 \[ -\frac{\left (4 c^2+5 c d-3 d^2\right ) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{30 f (c-d) \left (a^3 \sin (e+f x)+a^3\right )}-\frac{\left (4 c^2+5 c d-3 d^2\right ) \sqrt{c+d \sin (e+f x)} E\left (\frac{1}{2} \left (e+f x-\frac{\pi }{2}\right )|\frac{2 d}{c+d}\right )}{30 a^3 f (c-d) \sqrt{\frac{c+d \sin (e+f x)}{c+d}}}+\frac{(c+d) (4 c+5 d) \sqrt{\frac{c+d \sin (e+f x)}{c+d}} F\left (\frac{1}{2} \left (e+f x-\frac{\pi }{2}\right )|\frac{2 d}{c+d}\right )}{30 a^3 f \sqrt{c+d \sin (e+f x)}}-\frac{2 (c+2 d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{15 a f (a \sin (e+f x)+a)^2}-\frac{(c-d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{5 f (a \sin (e+f x)+a)^3} \]
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Rubi [A] time = 0.876879, antiderivative size = 323, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.259, Rules used = {2765, 2978, 2752, 2663, 2661, 2655, 2653} \[ -\frac{\left (4 c^2+5 c d-3 d^2\right ) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{30 f (c-d) \left (a^3 \sin (e+f x)+a^3\right )}-\frac{\left (4 c^2+5 c d-3 d^2\right ) \sqrt{c+d \sin (e+f x)} E\left (\frac{1}{2} \left (e+f x-\frac{\pi }{2}\right )|\frac{2 d}{c+d}\right )}{30 a^3 f (c-d) \sqrt{\frac{c+d \sin (e+f x)}{c+d}}}+\frac{(c+d) (4 c+5 d) \sqrt{\frac{c+d \sin (e+f x)}{c+d}} F\left (\frac{1}{2} \left (e+f x-\frac{\pi }{2}\right )|\frac{2 d}{c+d}\right )}{30 a^3 f \sqrt{c+d \sin (e+f x)}}-\frac{2 (c+2 d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{15 a f (a \sin (e+f x)+a)^2}-\frac{(c-d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{5 f (a \sin (e+f x)+a)^3} \]
Antiderivative was successfully verified.
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Rule 2765
Rule 2978
Rule 2752
Rule 2663
Rule 2661
Rule 2655
Rule 2653
Rubi steps
\begin{align*} \int \frac{(c+d \sin (e+f x))^{3/2}}{(a+a \sin (e+f x))^3} \, dx &=-\frac{(c-d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{5 f (a+a \sin (e+f x))^3}-\frac{\int \frac{-\frac{1}{2} a \left (4 c^2+7 c d-d^2\right )-\frac{1}{2} a d (3 c+7 d) \sin (e+f x)}{(a+a \sin (e+f x))^2 \sqrt{c+d \sin (e+f x)}} \, dx}{5 a^2}\\ &=-\frac{(c-d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{5 f (a+a \sin (e+f x))^3}-\frac{2 (c+2 d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{15 a f (a+a \sin (e+f x))^2}+\frac{\int \frac{\frac{1}{2} a^2 (c-d) \left (4 c^2+7 c d+d^2\right )+a^2 (c-d) d (c+2 d) \sin (e+f x)}{(a+a \sin (e+f x)) \sqrt{c+d \sin (e+f x)}} \, dx}{15 a^4 (c-d)}\\ &=-\frac{(c-d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{5 f (a+a \sin (e+f x))^3}-\frac{2 (c+2 d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{15 a f (a+a \sin (e+f x))^2}-\frac{\left (4 c^2+5 c d-3 d^2\right ) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{30 (c-d) f \left (a^3+a^3 \sin (e+f x)\right )}-\frac{\int \frac{\frac{1}{4} a^3 (c-d) d^2 (c+5 d)+\frac{1}{4} a^3 (c-d) d \left (4 c^2+5 c d-3 d^2\right ) \sin (e+f x)}{\sqrt{c+d \sin (e+f x)}} \, dx}{15 a^6 (c-d)^2}\\ &=-\frac{(c-d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{5 f (a+a \sin (e+f x))^3}-\frac{2 (c+2 d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{15 a f (a+a \sin (e+f x))^2}-\frac{\left (4 c^2+5 c d-3 d^2\right ) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{30 (c-d) f \left (a^3+a^3 \sin (e+f x)\right )}+\frac{((c+d) (4 c+5 d)) \int \frac{1}{\sqrt{c+d \sin (e+f x)}} \, dx}{60 a^3}-\frac{\left (4 c^2+5 c d-3 d^2\right ) \int \sqrt{c+d \sin (e+f x)} \, dx}{60 a^3 (c-d)}\\ &=-\frac{(c-d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{5 f (a+a \sin (e+f x))^3}-\frac{2 (c+2 d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{15 a f (a+a \sin (e+f x))^2}-\frac{\left (4 c^2+5 c d-3 d^2\right ) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{30 (c-d) f \left (a^3+a^3 \sin (e+f x)\right )}-\frac{\left (\left (4 c^2+5 c d-3 d^2\right ) \sqrt{c+d \sin (e+f x)}\right ) \int \sqrt{\frac{c}{c+d}+\frac{d \sin (e+f x)}{c+d}} \, dx}{60 a^3 (c-d) \sqrt{\frac{c+d \sin (e+f x)}{c+d}}}+\frac{\left ((c+d) (4 c+5 d) \sqrt{\frac{c+d \sin (e+f x)}{c+d}}\right ) \int \frac{1}{\sqrt{\frac{c}{c+d}+\frac{d \sin (e+f x)}{c+d}}} \, dx}{60 a^3 \sqrt{c+d \sin (e+f x)}}\\ &=-\frac{(c-d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{5 f (a+a \sin (e+f x))^3}-\frac{2 (c+2 d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{15 a f (a+a \sin (e+f x))^2}-\frac{\left (4 c^2+5 c d-3 d^2\right ) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{30 (c-d) f \left (a^3+a^3 \sin (e+f x)\right )}-\frac{\left (4 c^2+5 c d-3 d^2\right ) E\left (\frac{1}{2} \left (e-\frac{\pi }{2}+f x\right )|\frac{2 d}{c+d}\right ) \sqrt{c+d \sin (e+f x)}}{30 a^3 (c-d) f \sqrt{\frac{c+d \sin (e+f x)}{c+d}}}+\frac{(c+d) (4 c+5 d) F\left (\frac{1}{2} \left (e-\frac{\pi }{2}+f x\right )|\frac{2 d}{c+d}\right ) \sqrt{\frac{c+d \sin (e+f x)}{c+d}}}{30 a^3 f \sqrt{c+d \sin (e+f x)}}\\ \end{align*}
Mathematica [A] time = 6.24505, size = 631, normalized size = 1.95 \[ \frac{\left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )^6 \sqrt{c+d \sin (e+f x)} \left (\frac{4 c^2 \sin \left (\frac{1}{2} (e+f x)\right )+5 c d \sin \left (\frac{1}{2} (e+f x)\right )-3 d^2 \sin \left (\frac{1}{2} (e+f x)\right )}{15 (c-d) \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )}+\frac{d-c}{5 \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )^4}+\frac{2 \left (c \sin \left (\frac{1}{2} (e+f x)\right )-d \sin \left (\frac{1}{2} (e+f x)\right )\right )}{5 \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )^5}+\frac{4 \left (c \sin \left (\frac{1}{2} (e+f x)\right )+2 d \sin \left (\frac{1}{2} (e+f x)\right )\right )}{15 \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )^3}-\frac{2 (c+2 d)}{15 \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )^2}\right )}{f (a \sin (e+f x)+a)^3}-\frac{d \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )^6 \left (\frac{2 \left (4 c^2+5 c d-3 d^2\right ) \cos ^2(e+f x) \sqrt{c+d \sin (e+f x)}}{d \left (1-\sin ^2(e+f x)\right )}-\frac{\left (4 c^2+5 c d-3 d^2\right ) \left (\frac{2 (c+d) \sqrt{\frac{c+d \sin (e+f x)}{c+d}} E\left (\frac{1}{2} \left (-e-f x+\frac{\pi }{2}\right )|\frac{2 d}{c+d}\right )}{\sqrt{c+d \sin (e+f x)}}-\frac{2 c \sqrt{\frac{c+d \sin (e+f x)}{c+d}} F\left (\frac{1}{2} \left (-e-f x+\frac{\pi }{2}\right )|\frac{2 d}{c+d}\right )}{\sqrt{c+d \sin (e+f x)}}\right )}{d}-\frac{2 \left (c d+5 d^2\right ) \sqrt{\frac{c+d \sin (e+f x)}{c+d}} F\left (\frac{1}{2} \left (-e-f x+\frac{\pi }{2}\right )|\frac{2 d}{c+d}\right )}{\sqrt{c+d \sin (e+f x)}}\right )}{60 f (c-d) (a \sin (e+f x)+a)^3} \]
Antiderivative was successfully verified.
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Maple [B] time = 6.334, size = 1462, normalized size = 4.5 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (d \sin \left (f x + e\right ) + c\right )}^{\frac{3}{2}}}{{\left (a \sin \left (f x + e\right ) + a\right )}^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{{\left (d \sin \left (f x + e\right ) + c\right )}^{\frac{3}{2}}}{3 \, a^{3} \cos \left (f x + e\right )^{2} - 4 \, a^{3} +{\left (a^{3} \cos \left (f x + e\right )^{2} - 4 \, a^{3}\right )} \sin \left (f x + e\right )}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (d \sin \left (f x + e\right ) + c\right )}^{\frac{3}{2}}}{{\left (a \sin \left (f x + e\right ) + a\right )}^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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